ment aspx Hom Chapter 21 & 22 Begin Date: 82 18 12.0000 AM-Due Date: 9/20/2018 1
ID: 1880702 • Letter: M
Question
ment aspx Hom Chapter 21 & 22 Begin Date: 82 18 12.0000 AM-Due Date: 9/20/2018 11 59-00 PM End Date: 1 18 12:0000 AM (17%) Problem 4: An elecronac toy ss powered by three 1.58-V alkalne cells, each with an internal resistance of 0.0195 153 V carbon-zine dry cell, whose memal resistance is 0.115 All four cells are connected in seres as The tesistance ofthe rest ofthe crcut is 12.5 ad a 33% Part (a) What current, Ln amperes. Bou through the toy, crain eted! | 33% Part(b) How much power. P, in watts, ts supplied to the toy? 33% Part (c) The dry cel fails in such my that it meetin it, emfwhile tinernal renunte increases 2wline in ohes, of the failed dry cell? power of only 0.500 W wopplised to the toy. What is the inmernal resistance, t greatly That results in a reduced Crade Sammary Potential 100% uno coso atano coso tanho * Degrees RadiansExplanation / Answer
c)
let the internal resistance of dry cell be "R"
total resistance of the circuit is given as
Rtotal = R + 3 (0.0195) + 12.5 = 12.6 + R
V = total electric potential = 3 (1.58) + 1.53 = 6.27 Volts
Power is given as
P = V2/Rtotal
0.5 = (6.27)2/Rtotal
0.5 = (6.27)2/(12.6 + R)
R = 66.03 ohm
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