An inquisitive physics student and mountain climber climbs a 50.0 m cliff that o

Question

An inquisitive physics student and mountain climber climbs a 50.0 m cliff that overhangs a calm pool of water. He throws (not drops) two stones vertically downward, 1.00 s apart, and observes that they cause a single splash. The first stone has an initial speed of 1.90 m/s downward. Hint: Because the motion is only in the downward direction, choose the positive y-axis to point downward.

(a) How long after release of the first stone do the two stones hit the water?

(b) What initial velocity must the second stone have if they are to hit simultaneously?

Explanation / Answer

a)

Using 2nd equation of motion

d= ut+0.5gt^2

50= 1.9t+4.9t^2

Solving for t

t= 3 second

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b)

Time taken by second stone

T= 3-1= 2 second

d= u'* T+ 0.5*gT^2

50= u*2+4.9*2^2

u= 15.2 m/s

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Comment in case any doubt.. good luck

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