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HW #3: 2D & 3D Motion Begin Date 7/11/2018 12:01:00 AM D Date 9/19/2018 11:59:00

ID: 1880758 • Letter: H

Question

HW #3: 2D & 3D Motion Begin Date 7/11/2018 12:01:00 AM D Date 9/19/2018 11:59:00 PM End Date 1203 1/2018 11:59:00 PM (7%) Problem 4: During a baseball game, a baseball is struck at ground level by a batter. The ball leaves the baseball bat with an initial velocity v0 = 47 m/s at an angle = 26° above horizontal. Let the origin of the Cartesian coordinate system be the ball's position the instant it leaves the bat. Air resistance may be ignored throughout this problem y Otheexpertta.com 20% Part (a) Express the magnitude of the ball's initial horizontal velocity var in terms of 0 and 0. or 42.24 Grade Summary Deductions 0%

Explanation / Answer

4. DURING BASEBALL GAME

vo = 47 m/s

tehta = 26 deg

ignoring air resistance

a. horizontal velocity = vox

vox = vo*cos(theta)

b. voy = vo*sin(theta)

c. hmax = ?

now, y = vo*sin(theta)t - gt^2/2

at h max, dy/dt = 0

vo*sin(theta) = gt

t = vo*sin(tehta)/g

hmax = vo*sin(theta)*vo*sin(theta)/g - g*vo^2*sin^2(theta)/2g^2

hmax = vo^2*sin^2(theta)/g - vo^2*sin^2(theta)/2g

hmax = vo^2*sin^2(theta)/2g = 47^2*sin^2(26)/2g = 21.6361824 m

e. time of flight = 2t = 2vo*sin(theta)/g

xmax = vo*cos(theta)*2vo*sin(theta)/g = vo^2*sin(2*theta)/g = 177.44299232 m