HW #3: 2D & 3D Motion Begin Date 7/11/2018 12:01:00 AM D Date 9/19/2018 11:59:00
ID: 1880758 • Letter: H
Question
HW #3: 2D & 3D Motion Begin Date 7/11/2018 12:01:00 AM D Date 9/19/2018 11:59:00 PM End Date 1203 1/2018 11:59:00 PM (7%) Problem 4: During a baseball game, a baseball is struck at ground level by a batter. The ball leaves the baseball bat with an initial velocity v0 = 47 m/s at an angle = 26° above horizontal. Let the origin of the Cartesian coordinate system be the ball's position the instant it leaves the bat. Air resistance may be ignored throughout this problem y Otheexpertta.com 20% Part (a) Express the magnitude of the ball's initial horizontal velocity var in terms of 0 and 0. or 42.24 Grade Summary Deductions 0%Explanation / Answer
4. DURING BASEBALL GAME
vo = 47 m/s
tehta = 26 deg
ignoring air resistance
a. horizontal velocity = vox
vox = vo*cos(theta)
b. voy = vo*sin(theta)
c. hmax = ?
now, y = vo*sin(theta)t - gt^2/2
at h max, dy/dt = 0
vo*sin(theta) = gt
t = vo*sin(tehta)/g
hmax = vo*sin(theta)*vo*sin(theta)/g - g*vo^2*sin^2(theta)/2g^2
hmax = vo^2*sin^2(theta)/g - vo^2*sin^2(theta)/2g
hmax = vo^2*sin^2(theta)/2g = 47^2*sin^2(26)/2g = 21.6361824 m
e. time of flight = 2t = 2vo*sin(theta)/g
xmax = vo*cos(theta)*2vo*sin(theta)/g = vo^2*sin(2*theta)/g = 177.44299232 m
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