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(7%) Problem 6: A projectile is launched at ground level with an initial speed o

ID: 1880775 • Letter: #

Question

(7%) Problem 6: A projectile is launched at ground level with an initial speed of 39 m/s, at an angle of 35° above the horizontal. It strikes a target above the ground 2.5 seconds later 50% Part (a) What is the horizontal distance, in metres, from where the projectile was launched to where it lands? Grade Summa Deductions Potential x-8 .941 Submissions Attempts remai (0% per attemp detailed view 78 9 HOMHE tan) u cotan)asin)acos() sinh0 cosO atan)acotan() 123 END ( BACKSPACEDEL CLEAR )cotanh(O 0 Degrees O Radians Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 4 Feedback: 0% deduction per feedback 50% Part (b) What is the vertical distance, in meters, from where the projectile was launched to where it lands?

Explanation / Answer

Given,

vi = 39 m/s ; theta = 35 deg ; t = 2.5 s

a)we know that

x = v cos(theta) t

x = 39 x cos35 x 2.5 = 79.87 m

Hence, X = 79.87 m

b)vertical distance will be:

y = v sin(theta) t - 1/2 g t^2

Y = 39 x sin35 x 2.5 - 0.5 x 9.81 x 2.5^2 = 25.27 m

Hence, Y = 25.27 m