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Please answer all parts clearly and correctly What is the magnitude of the elect

ID: 1880863 • Letter: P

Question

Please answer all parts clearly and correctly

What is the magnitude of the electric field at point P, which is on the positive x-axis at z 45.0 cm? A ring-shaped conductor with radius 2.60 cm has a total positive charge Q 0.120 nC uniformly distributed around it. Figure 1) N/C Submit Part B What is the direction of the electric field at point P? "x-direction Submit t Answer Part C A particle with a charge of 2.70 C is placed at the point P described in part A What is tne magnitude of the force exerted by the particle on the ring? Figure 1 of 1 ds Submit t Answer dE 0 Part D dE What is the direction of the force exerted by the particle on the ring? O x-direction

Explanation / Answer

a)

Electric field is given by

E= kqx/(x^2+a^2)^(3/2)

=9*10^9*0.12*10^-90.45/(0.026^2+0.45^2)^(3/2)

= 5.307 N/C

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b) directed directed along +x axis

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c)

F= qE= 2.7*10^-6*5.307= 14.328 N

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d) directed opposite to the electric field,i.e. towards -- axis.

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Comment in case any doubt.. good luck

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