Georgia ,e). Homepage-PHYS-1112K-A 11× Course Horne vellum .ecollege.com/course.

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Georgia ,e). Homepage-PHYS-1112K-A 11× Course Horne vellum .ecollege.com/course.html?courseid-14900936&OpenVellumHMAC-531 1 6c2c8c112ee868691 84c54516ccf#10001 xC What Is The Strength Of The EX Phys1112K-A Course Home KAssignment 3. Electric field and force Problem 20.40 13 of 13 Constarts 1 Poriodis Tablo Part A Raindrops acquire an electric charge as they fall. Suppose a 22-mm-diameter drop has a charge of +15 pC. If the strength of the earth's electric field is 100 N/C, how does the magnitude of the electric force the droplet compare to the weight force? Pectr Submit Previous Answers Request Answer Incorrect; Try Again: 5 attempts remaining

Explanation / Answer

Step 1:

Electric force on raindrop will be

Fe = q*E

q = 15 pC = 15*10^-12 C

E = 100 N/C

So,

Fe = 15*10^-12*100 = 1.5*10^-9 N

Step 2:

Weight force on drop will be

Fg = m*g

g = 9.81 m/sec^2

m = mass of rain drop = density*Volume

density of water = 1000 kg/m^3

Volume = 4*pi*r^3/3

r = 2.2 mm/2 = 1.1 mm

Volume = 4*pi*(1.1*10^-3)^3/3 = 5.57*10^-9 m^3

So,

mass = 1000*5.57*10^-9 = 5.57*10^-6 N

Fg = 5.57*10^-6*9.8 = 5.46*10^-5

Now

Step 3:

Fe/Fg = (1.5*10^-9)/(5.46*10^-5)

Fe/Fg = 27.5*10^-6

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