question 10 and 11 QUESTION 10 1 points A parallel plate capacitor has a dielect
ID: 1880993 • Letter: Q
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question 10 and 11
QUESTION 10 1 points A parallel plate capacitor has a dielectric with constant 3.5. The plates are circular with radius 0.07 m, and the separation gap is 0.375 mm What energy may be stored in this capacitor if 1250 V is the applied voltage? 0 9.9 x 104 O 2.8 x 104 O 3.5 x 103 O 2.0 x 103 QUESTION 11 1 points Sa A parallel plate capacitor has plates each of area 100 cm 2 and with separation 0.25 mm. If this ca pacitor is charged with 25 pC, what is the average charge density on the positive plate? O 400 pC/m O 40 x 1012 C/m2 O 25 pC/m 2.5 nC/m 8.8 1012 c/m Save and Subm bmit Click Save All Answers to save all anstwers EtExplanation / Answer
10)
Capacitance is given by:
C = K*epsoleneo*A/d
Given:
A = pi*r^2
= pi*(0.07 m)^2
= 1.54*10^-2 m^2
d = 0.375 mm
= 3.75*10^-4 m
k = 3.5
Use:
C = k*epsoleneo*A/d
= 3.5*8.854*10^-12*1.54*10^-2/3.75*10^-4
= 1.273*10^-9 F
Energy stored,
E = 0.5*C*V^2
= 0.5*(1.273*10^-9 F)*(1250 V)^2
= 9.9*10^-4 J
Answer: option 1
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