urzAM ECTORS AND NAME: tics . Mushrooms launch their spores using a catapult mec

Question

urzAM ECTORS AND NAME: tics . Mushrooms launch their spores using a catapult mechanism designed by nature. As water condenses from the air onto a spore that is attached to the mushroom, a drop grows on one side of the spore and film grows on the other side. The spore is bent over by the drops weight, but when the film reaches the drop, the drop's water suddenly spreads into the film and the spore springs upward so rapidly that is slung off into the air. The spore reaches a speed of 1.6m/s over a distance of 5 x10*m. Hint: I know this sounds hard when put in a real life situation but it's really just a 1D kinematics problem. Use a laundry list! a. What is spore's acceleration? b. If 1g is 9.8 m/s? how many g's does the spore experience? 2. Given: -2i +3j-4k, B--31+4j +2k, and C-7i-8j, find CO(ADB)

Explanation / Answer

Information: as per the rules of the chegg, you need to post one question at a time. but you have posted more than one questions.

so, i am answering question 1 and 4. only

Answer for question 1:

Given

v= 1.6 m/s

l = 5.0 x10-6 m

a)

v= vf ; vi=0

we know the equations

v=0=at

v=at;

l= vt/2 and t=2l/v

v=at= a(2l/v)

by solving these two equations

a = v2/2l

a = (1.6)2/ (2x5.0x10-6)

a = 2.56/ (1x10-5)

a = 256000 m/s2

b) Now we need to calculate acceleration in terms of g; g= 9.8m/s2

ag = a/g = 256000/ 9.8

ag = 26122.45g

Answer for question 4.

Here we need to find height, h.

By using the following formula

d= (v2 sin 2) / g

sin 2 = d x g /v2

here given d= 45.7m, g=9.8m/s2, v=460m/s

sin2 = (45.7 x 9.8) / (4602) = 447.86/211600

sin 2 = 0.00216

= 0.0606o

tan = h/d

tan = (h)/ (45.7)

h = tan x 45.7

h= tan( 0.0606) x45.7

h = 0.001 x 45.7

h= 0.0457m or 4.57cm

The mission here is to find h. We can do this by using the range d to find then use some simple trigonometry to get h.

The range is given by:

d=v2sin2g

sin2=dgv2

=45.7×9.84602

sin2=0.002116

2=0.1212

=0.0606

Now looking at the diagram we can say that:

tan=h45

h=45.7×tan

h=45.5×0.001

h=0.0457m

h=4.57cm

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