| | | + https i galileo.johnabbott.qc.ca., res/msu/kashy/physicsLib02/52-Electri
ID: 1881191 • Letter: #
Question
| | | + https i galileo.johnabbott.qc.ca., res/msu/kashy/physicsLib02/52-ElectricHeld/2qEfieldb.problem#0-LON-CAPA Q3: Electric field map C Reader O Chegg Study G. Chegg Study | G (2.211cdot10A7). LON-CAPA Two Charges, Q. MOST LIKELY T Electric Field P Kelli Dimayuga (Student section: 04) Electricity and MagnetismF18Mike Richard Messages Courses Help Logout Main Menu Contents Grades Syllabus TimerNotes EvaluateFeedback PrintInfo Course Contents » » A#2 » 3: Electric field map he electric field o charges in the plane of the paper is represented by the dashed lines and arrows below 3- elect the best response for each statement below. (Use 'North' towards top of page, and East' to the right.) False The force on a (+) test charge at K is zero South The force on a (+) test charge at S is directed East The force on a (-) test charge at N is directed Greater than The magnitude of the E-field at P is than at R Less than The magnitude of the charge on the left is... that on the right. False The sign of the charge on the left is positive Submit AnswerIn Tries 3/99 Previous Tries Post Discussion Send FeedbackExplanation / Answer
Key points to remember:
"False" The force on a (+) test charge at K is zero. Because there will be repulsion force present as the charge on left is positive.
"East" The force on a (+) test charge at S is directed towards east because the left hand side charge is (+). So it will repel the (+) test charge in opposite direction i.e. towards right. And magnetic field towards right would be East as stated earlier.
"North" The force on a (-) test charge at N is directed towards north because the right hand side charge is (-). So it will repel the (-) test charge in opposite direction i.e. in upward direction. And upward direction is denoted as North.
"Less" The magnitude of the E-field at P is less than at R because more the distance from the point charge, lesser will be the force experienced.
"Less than" The magnitude o=f the charge on the left is less than that on the right. It is because the total number of magnetic lines going out of (+) charge is lesser than total number of magnetic lines coming in (-) charge.
"True" The sign of the charge on the left is positive because magnetic lines are going out of it. And this happens when the charge present is (+).
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.