please answer #3!!! I can\'t get it Syst Systa A person with mass my - 60 kg sta

Question

please answer #3!!! I can't get it

Syst Systa A person with mass my - 60 kg stands at the left end of a uniform beam with mass m2 - 103 kg and a length L 2.6 m. Another person with mass ms -67 kg stands on the far right end of the beam and holds a medicine ball with mass ms 8 kg (assume that the medicine ball is at the far right end of the beam as well). Let the origin of our coordinate ing. Assume there is no friction between the beam and floor 1) What is the location of the center of mass of the system? 1.38 m Submt

Explanation / Answer

Let's say the beam moves "d" to the right as a result of the toss.
1.38 = [(60+8)*d + 103*(1.3+d) + 67*(2.6+d)] / 238
for d in meters. This solves to d = 0.0854 m

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