Problem 25.43 - Enhanced - with Video Solution A proton\'s speed as it passes po

Question

Problem 25.43 - Enhanced - with Video Solution A proton's speed as it passes point A is 4.00×104 m/s , t follows the trajectory shown in the figure (Figure 1) Part A What is the proton's speed at point B? Express your answer with the appropriate units. You may want to review (Page 687) For help with math skills, you may want to review: Mathematical Expressions Involving Squares For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Capacitor plates Value Units Submit Return to Assignment Provide Feedback Figure 1 of 1 0 10 V-10 V

Explanation / Answer

potential difference = 40 V

work done on proton = q*delta V

= (1.602*10^-19 C)* 40 V

= 6.41*10^-18 J

Now use:

work done = 0.5*m*(vf^2 - vi^2)

6.41*10^-18 = 0.5* 1.673*10^-27 * (vf^2 - (4.00*10^4)^2)

(vf^2 - (4.00*10^4)^2) = 7.66*10^9

(vf^2 - 1.60*10^9) = 7.66*10^9

vf^2 = 9.26*10^9

vf = 9.62*10^4 m/s

Answer: 9.62*10^4 m/s

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