Percent different for y? And the acceleration due to gravity? Percent different

Question

Percent different for y? And the acceleration due to gravity? Percent different for y? And the acceleration due to gravity? In the book is say ((v1-v2)/(v2+v1/2))*100%. Which one are the v’s? As for the acceleration, I’m just lost on what formula I should uses ?. the faliliy Data Table 6.2 Dependence of Falling height y=-nis the same for all falling balls Average falling Acceleration dug gravity from equation (7,g m/s Falling time t,s time Mass of the ball, Trial1 Trial 2 Trial 3 Your Reaction Time 2. Distance y-m. reaction time from equation (6.10) Freaction Fig. 71. the main as Let us height h is The land t hits the gro ander the infl

Explanation / Answer

For the Y part

Don't worry it is simple as for the date table 6.1 you have 2 y right ,one is the first coloumn and the other is a calculated one in the 6 th coloumn .Take the difference and divide it with the original or the data in the first coloumn and multiply it by 100 like

{(ycalculated-yoriginal)/yoriginal}*100%.

For the g part

Now for the table 6.2 we have 3 trials which are t in secs and s=1 m

Use the formula S=u*t+0.5*g*t2 U being 0 as the body was at rest and t being the average one in each case or the data in the 3rd coloumn

Calculate g in each case for the table 6.2.

Now take the first 2 trials of 6.2 table and calculate V1 for trial1 and V2 for trial 2 using equation v2-u2=2*g*S and use ((v1-v2)/(v2+v1/2))*100%

As I can see you require to calculate the % error in g

{(gfromgraph-9.8)/9.8}*100%

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