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Biction A xk Fakebook x G Christian X C Secure https://session masteringphysics.com/myct/itemView?offset nextBassignmentProblemiD-102120913 AP Physics 1 2018-2019 JCHS (forces (N2L and N3L) [Statics and Dynamics] Problem 5.60 Con s 95 kg, stands on a bathroom scale in an elevator. The scale reads 830 N tor the fist 3.0 s after the elevator starts to move, than 930 N for the next 3.0 Part A What is the elevators velocity 6.0 s after starting? Express your answer with the appropriate units. Enter positive value if the motion is upward and negative value if the motion is downward. x 10" 1.06 t%- Submit Incorrect: Try Again: 4 attempts remaining Provide Foedback Type here to search

Explanation / Answer

(95 x g) = weight of (95 x 9.8) = 931N.
The elevator accelerates DOWN for 3 secs., at a rate of (f/m) = (931 - 830)/95 = 1.063m/sec^2.
Velocity attained at 3 secs = (at) = (1.063 x 3) = 3.19m/sec.

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