| FULL SCREEN | | PRINTER VERSION BACK NEXT Chapter 22, Problem 057 An electric

Question

| FULL SCREEN | | PRINTER VERSION BACK NEXT Chapter 22, Problem 057 An electric dipole consisting of charges of magnitude 4.80 nC separated by 9.30 m is in an electric field of strength 1280 NC, what are (a) the magnitude of the electric dipole moment and (b) the difference between the potential energies for dipole orientations parallel and antiparallel to ? Units (a) Number (b) Number Click if you would like to Show Work for this question: Units Open Show Work Question Attempts: 0 of 8 used SAVE FOR LATER SUBMIT ANSWER

Explanation / Answer

Here,

a) magnitude of dipole moment = charge * separation

magnitude of dipole moment = 4.8 *10^-9 * 9.3 *10^-6 C.m

magnitude of dipole moment = 4.46 *10^-14 C.m

the magnitude of dipole moment is 4.46 *10-14 C.m

b)

NOw, for the difference in potential energy

difference in potential energy = 2 * E*dipole moment

difference in potential energy = 2 * 1280 * 4.46 *10^-14

difference in potential energy = 1.14 *10^-10 J

the difference in potential energy is 1.14 *10-10 J

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