Gayle runs at a speed of 3.30 m/s and dives on a sled, initially at rest on the
ID: 1882365 • Letter: G
Question
Gayle runs at a speed of 3.30 m/s and dives on a sled, initially at rest on the top of a frictionless snow-covered hill. After she has descended a vertical distance of 5.00 m, her brother, who is initially at rest, hops on her back and together they continue down the hill. What is their speed at the bottom of the hill if the total vertical drop is 15.0 m? Gayle's mass is 47.0 kg, the sled has a mass of 5.25 kg and her brother has a mass of 30.0 kg.
16.72x Your response is within 10% of the correct value. to minimize roundoff error. m/sExplanation / Answer
As we know that;
Conservation of energy;
= 0.5m1u^2 + m1gh1 + m2gh2 = 0.5*(m1+m2)v^2
= 0.5* 47* 3.30^2 + 47*9.8*15+ 5.25 *9.8*(15-5) = 0.5*(47+5.25)*v^2
= 7679.415= 26 v^2
= v^2= 7679.415/26
= v^2= 295.362
= v = (295.362)
= v = 19.323 m/s
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