25% Part (a) Find the total charge stored in the system if the capacitors are co

Question

25% Part (a) Find the total charge stored in the system if the capacitors are connected to the battery in series in C. Grade Summary Deductions Potential 0% 100% sin cotanO asin0 acos0 atan) acotan) sinh(0 cosh0nh cotanh0 Submissions tan() | | ( 78 9 Attempts remaining: S % per attempt) detailed view 0 END Degrees O Radians CLEAR Submit I give up! Hints: 1% deduction per hint. Hints remaining: 2 Feedback: 1% deduction per feedback 25% Part (b) Find the energy stored in the system if the capacitors are connected to the battery in series in J 25% Part (c) Find the charge if the capacitors are connected to the battery in parallel in C. 25% Part (d) Find the energy stored if the capacitors are connected to the battery in parallel in J.

Explanation / Answer

part(a)

In series

total capacitance C_tot = (C1*C2)/(C1+C2) = (2.4*10^-6*9.05*10^-6)/(2.4*10^-6 + 9.05*10^-6)

C_tot = 1.90*10^-6 F

total charge Qtotal = C_tot*V = 17.1*10^-6 C = 17.1 uC

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part(b)

energy stored E = (1/2)*Ctot*V^2 = (1/2)*1.9*10^-6*9^2 = 7.695*10^-5 J

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part(c)

In parallel combination

Ctot = C1 + C2 = 11.45*10^-6 F

total charge Qtot = C_tot*V = 103.05*10^-6 C

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part(d)

energy stored E = (1/2)*Ctot*V^2 = (1/2)*11.45*10^-6*9^2 = 46.37*10^-5 J

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