NOTES: You will need to enter units for these answers. Remember that m/s 2 is en

Question

NOTES: You will need to enter units for these answers. Remember that m/s2 is entered as m/s^2. Your answers must be entered with THREE SIGNIFICANT FIGURES. Remember that velocity and acceleration are vectors and so you will need to indicate their direction with a positive or negative sign. Positive is "up."

A ball is thrown vertically upward, starting at y = 0, with a velocity of 11.0 m/s. Take "up" to be the positive direction for this problem.

(a) Calculate the maximum vertical displacement of the ball.
(For all of these: Enter THREE sig figs and units)

(b) Calculate the time required for the ball to reach its highest point.

(c) What is the ball's acceleration when it is at its highest point?

(d) How long does the ball take to fall back to the point y = 0 after it reaches its highest point?

(e) What is its velocity when it returns to the level from which it started (y = 0)? Remember that velocity is a vector.

Explanation / Answer

Here ,

u = 11 m/s

a)

maximum vertical displacement = u^2/(2g)

maximum vertical displacement = 11^2/(2 * 9.8)

maximum vertical displacement = 6.17 m

b) to reach the highest point

time required for the ball = 11/9.8

time required for the ball = 1.12 s

c)

at the highest point

ball's acceleration = -g

ball's acceleration = - 9.81 m/s^2

d)

total time taken = 2 * time taken to reach highest point

total time taken = 2 * 1.12 s

total time taken = 2.24 s

e)

at the same point

velocity = - 11.0 m/s

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