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(9%) Problem 10: During a baseball game, a baseball is struck at ground level by

ID: 1882620 • Letter: #

Question

(9%) Problem 10: During a baseball game, a baseball is struck at ground level by a batter. The ball leaves the baseball bat with an initial velocity vo-36 m/s at an angle 6 - 22° above horizontal. Let the origin of the Cartesian coordinate system be the ball':s position the instant it leaves the bat. Air resistance may be ignored throughout this problem ©theexpertta.com 20% Part (a) Express the magnitude of the ball's initial horizontal velocity v0x in terms of vo and Grade Summary Deductions Potential Late Work % 80% Late Potential 80% Ox 0% cos(a) sin( ) | | cos() sin() | | cos(0) sin(9) Submissions Attempts remaining: 10 % per attempt) detailed view 0 END BACKSPACE DELI CLEAR Submit Hint I give up! Hints: 1% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback 20% Part (b) Express the magnitude of the ball's initial vertical velocity voy in terms of vo and 20% Part (c) Find the ball's maximum vertical height hmur In meters above the ground 20% Part (d) Create an expression in terms of v03, and g for the time tn it takes the ball to travel to its maximum vertical height 20% Part (e) Calculate the horizontal distance-max In meters the ball has traveled when it returns to ground level

Explanation / Answer

as g=9.8m/s^2
(a) v0x=v0cos = 36cos(22).......this is answer

= 33.38 m/s
(b) v0y=v0sin = 36sin(22)...this is answer

= 13.49 m/s
(c) hmax=(v0sin)^2/2g
hmax= (13.49^2)/(2*9.8)= 9.28 m
(d) tmax=(v0sin)/g ...this is the answer.
tmax= 13.49/9.8= 1.38 sec
(e) t=2v0y/g
t= 2*13.49/9.8= 2.75 s
xmax=v0xt = 33.38*2.75= 91.8 m....ans

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