(c3p28) A passenger rushing to catch a plane at the airport walks on a moving si

Question

(c3p28) A passenger rushing to catch a plane at the airport walks on a moving sidewalk at a speed of 3.5 km/h relative to the sidewalk in the direction that the sidewalk is moving. The sidewalk is 125 m long and moves with a steady velocity of 2.0 km/h. How long (in s) does it take for the passenger to get from one end of the sidewalk to the other, that i to cover the 125 m? Submit Answer Tries 0/10 How much time does the passenger save by taking the moving sidewalk instead of just walking beside it? Submit Answer Tries 0/10 Through what distance does the passenger walk relative to the moving sidewalk? Submit Answer Tries 0/10 If the passenger's stride is 90 cm, how many steps are taken in going from one end of the moving sidewalk to the other? Submit Answer Tries 0/10

Explanation / Answer

Given,

vp = 3.5 km/h = 0.97 m/s ; D = 125 m ; vs = 2 km/h = 0.56 m/s

1)since both are moving in the same directiion

So the man moves at

ve = 0.97 + 0.56 = 1.53 m/s

v = d/t => t = d/v

t = 125/1.53 = 81.7 s

Hence, t = 81.7 s

2)if the passenger did not take the sidewalk, he will have velocity, vp = 3.5 km/h = 0.97 m/s

tp = 125/0.97 = 128.9 s

time saved = 128.9 - 81.6 = 47.3 s

Hence, t(saved) = 47.3 s

3)D' = t vp

D' = 81.7 x 0.97 = 79.25 m

Hence, D' = 79.25 m

4)n = D'/L

n = 79.25/0.9 = 88 strides

Hence, n = 88 strides

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