lorida-PHY 2054-Fall18-BOSSE Activities and Due Dates Postlecture HW 1b 9/26/201

Question

lorida-PHY 2054-Fall18-BOSSE Activities and Due Dates Postlecture HW 1b 9/26/2018 11:59 PM A 62.2/100 Gradebool estion 4 of 15 Sapling Learning A proton and an electron are fixed in space with a separation of 863 nm. Calculate the electric potential at the midpoint between the two particles. Find the magnitude and direction of the electric field at the same point. Potential: Number Magnitude of field Number N/C Direction of field: O Toward the proton Toward the electron O Another direction O Undetermined O Previous Check Ansaer Next Ex Hint us l careers privacy policy. ¡ terms of use | contactus

Explanation / Answer

here,

charge on electron , q1 = - 1.6 * 10^-19 C

charge on proton , q2 = 1.6 * 10^-19 C

sepration , r = 863 nm = 8.63 * 10^-7 m

the electric potential at the midpoint , V = K * q1 /r/2 + K * q2 /(r/2)

V = 9 * 10^9 * 1.6 * 10^-19 /( r/2) - 9 * 10^9 * 1.6 * 10^-19 /( r/2)

V = 0 V

the magnitude of electric feild at the midpoint , E = K * q1 /(r/2)^2 + K * q2 /(r/2)^2

E = 2 * 9 * 10^9 * 1.6 * 10^-19 /( (8.63 * 10^-7 /2)^2)

E = 1.55 * 10^4 N/C

the direction of feild is Towards the electron

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