(33%) Problem 3: A thin and uniformly positively charged ring of radius R = 0.25

Question

(33%) Problem 3: A thin and uniformly positively charged ring of radius R = 0.25 m and net electric charge Q = 7.5 mC is lying in the x-y plane. The z-axis is perpendicular to the plane of the ring and passes through the center of the ring. The ring is rotating around the z-axis with angular frequency = 2.5 rad/s in the presence of an external uniform magnetic field directed perpendicular to the plane of the ring (i.e., parallel to the angular velocity vector) x X x X x X X X x X X X What is the magnetic potential energy (in W) of the ring if the magnitude of the external magnetic field is 075 T Grade Summary Deductions m,dipole 4.8 0% 100 %

Explanation / Answer

Solution,

Current, I = Q/t

Time t = 2 pi/w

I = Qw/2 pi

U = - QwAB cos(theta) / 2 pi

U = - (0.0075 x 2.5 x pi x 0.25^2 x 0.75 x cos0) / 2 pi

U = - 439.45 uJ

Magnitude is 439.45 uJ (Ans)

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