A 75.0 cm wire of mass 8.40g is tied at both ends and adjusted to a tension of 3

Question

A 75.0 cm wire of mass 8.40g is tied at both ends and adjusted to a tension of 39.0N.
A)when it is vibrating in its second overtone, find the frequency at which it is vibrating. ?Hz
B) when it is vibrating in its second overtone, find the wavelength at which it is vibrating. ?m
C) when it is vibrating in its second overtone, find the frequency of the sound waves it is producing. ?Hz
D) when it is vibrating in its second overtone, find the wavelength of the sound waves it’s producing. ?m A 75.0 cm wire of mass 8.40g is tied at both ends and adjusted to a tension of 39.0N.
A)when it is vibrating in its second overtone, find the frequency at which it is vibrating. ?Hz
B) when it is vibrating in its second overtone, find the wavelength at which it is vibrating. ?m
C) when it is vibrating in its second overtone, find the frequency of the sound waves it is producing. ?Hz
D) when it is vibrating in its second overtone, find the wavelength of the sound waves it’s producing. ?m
A)when it is vibrating in its second overtone, find the frequency at which it is vibrating. ?Hz
B) when it is vibrating in its second overtone, find the wavelength at which it is vibrating. ?m
C) when it is vibrating in its second overtone, find the frequency of the sound waves it is producing. ?Hz
D) when it is vibrating in its second overtone, find the wavelength of the sound waves it’s producing. ?m

Explanation / Answer

a)  frequency of  second overtone = [3 / 2 L] * sqrt[T/(m/L)] = [3 / 2 L] * sqrt[T L / m]

= [3 / (2 * 0.75)] * sqrt [39 * 0.85 / 0.0084]

= 118 Hz

b) lambda = 2 L / 3

= (2 * 0.75) / 3 = 0.5 m

c) frequency of the sound waves it is producing = 118 Hz

d) wavelength = 343 / 118 = 2.91 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.