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What is the direction of the electric field? What is the magnitude of the electr

ID: 1883620 • Letter: W

Question


What is the direction of the electric field?
What is the magnitude of the electric field at z0. (N/C) ?

At large distances from the circle, what is the size of the dipole moment? (C*m) p -->

A circle of radius 5 cm has a positive charge 3 nC dis- tributed along its left half and negative charge -3 nC along its right half. (See Fig ure.) For the following, assume that the ty direction is up, the +x direction is to the right, and the +z direction is out of the page. At dis- tance zo from the center of the circle Choices: +x,-x, +y,-y, +z,-z. What is the direction of the electric field? . ou are correct. What is the magnitude of the electric field at o (N/C)? HINTS: * The length of a small piece of arc, ds, in·circle of radius R is given by: ds- Rde . Make sure you are only integrating the components that do not cancel out due to symmetry At large distances from the circle, what is the sire of the dipole moment, 7(C-m)? HINTS . Use the binomial expansion of the expression you found in the previous part to find the field far away from the circle

Explanation / Answer

Firstly we find direction of An electric field is generated by electric charge and tells us the force per unit charge at all locations in space around a charge distribution   The electric field extends out into space around the charge distribution The electric field exerts a force on the test charge in a given direction. The force exerted is proportional to the charge of the test charge electric field is “the force per unit charge” is written as
E=Fqtest
E=Fqtest
where we are considering only electric forces. Note that the electric field is a vector field that points in the same direction as the force on the positive test charge. The units of electric field are N/C. Then we find the magnitude Now consider the magnitude of the force between this point charge Q and the test charge is given by Coulomb’s law:
F=k|Qqtest|r2
F=k| Qqtest |r2
where the absolute value is used since we only consider the magnitude of the force. The magnitude of the electric field is then.   
E=Fqtest=k|Q|r2   This equation gives the magnitude of the electric field created by a point charge Q. The distance r in the denominator is the distance from the point charge Q (or from the center of a spherical charge) to the point of interest. We know thatThe larger the difference in electronegativity, the larger the dipole moment. The distance between the charge separation is also a deciding factor into the size of the dipole moment. The dipole moment is a measure of the polarity of the molecule.

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