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in Lout 1.) The figure shows shows the position of two equal charges q 6 nC. i 1

ID: 1883663 • Letter: I

Question

in Lout 1.) The figure shows shows the position of two equal charges q 6 nC. i 1m 6 nC 6 nC 1 m 2 m a. [5 pts] Find the total Electric Field at point A, EA b. [5 pts] Find the total Electric Field at point B, Ep. c. [5 pts] Find the total Electric Field at point C, Ec d. [5 pts] Find the total Electric Potential at point A, VA e. [5 pts] Find the total Electric Potential at point B, VB. f. [5 pts] Find the total Electric Potential at point C, Vc. g. [5 pts] A new charge qn 2 nC, and mass mn -8 x 1012 kg is placed at point A. What is the instantaneous acceleration, a, of the new charge? 1. speed, v, when it arrives at point B?

Explanation / Answer

1. given two equal charges

q = 6 nC

a. at point A

Ea = kq/1 i - kq/9 i = 8kq i / 9 = 47.893333 i V/m ( + x axis)

2. Eb = 0 V/m ( as this point is midway between the two charges sop from symmetry the electric field is 0)

3. Ec = (kq/2)(cos(45)i + sin(45)j) + (kq/10)(-3i + j)/sqrt(10)

Ec = 13.9379510i + 20.7532915008 j V/m

4. Va = kq(1/1 + 1/3) = 4kq/3 = 71.84 V

5. Vb = 2kq/2 = 53.88 V

6. Vc = kq(1/sqrt(2) + 1/sqrt(10)) = 55.1372654 V