1(.) Timer notes Evaluate au Feedback- Print (info uret contents Assignment 5 Al

Question

1(.) Timer notes Evaluate au Feedback- Print (info uret contents Assignment 5 Alpha Particle in Magnetic Field Alpha Particle in Magnetic Field Due in 13 hours, 21 minutes An alpha partce (the nucleus of a helium atom formed by 2 protons and 2 neutrons with charge q +2(1.6 x 10-19 C field of 0.530 tesle at a velocity of 3.60E +6 m/s ; calculate the magnitude of the magnetic force exerted on it. Submt Answer Tries 0/10 culate the acceleration of the alpha particle. Submit Answer Tries 0/10 What will be the radius of curvature of the path followed by the alpha particle in the magnetic freld? Submit Answer Tries 0/10 What would be the force on the alpha particle if it were traveling parallel to the magnetic field lines? Submit Answer Tries 0/10 al Post Discussion

Explanation / Answer

magnetic force Fb = q*v*B*sintheta

part(a)

theta = 90

charge q = 2*(1.6*10^-19) C

B = 0.53 tesla

v = 3.6*10^6 m/s

magnetic force Fb = 2*(1.6*10^-19)*3.6*10^6*0.53*sin90 = 6.11*10^-13 N

=========================================

acceleration a = Fb/m

mass m = 4*1.67*10^-27 kg

acceleration a = (6.11*10^-13) /(4*1.67*10^-27)

acceleration a = 9.15*10^13 m/s^2

---------------------------

In circular motion

a = acceleration = v^2/r

radius r = v^2/a

radius r = 0.142 m

===================

theta = 0

magnetic force Fb = q*v*B*sin0 = 0

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.