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ok I do not understand these explanations at all lol can anyone explain this to

ID: 1884219 • Letter: O

Question

ok I do not understand these explanations at all lol can anyone explain this to me in a way that will make sense

Problem 3 A spider, with a mass of 0.4g, is hanging on a single thread of its silk while being blown by a horizontal wind. The spider silk thread has a radius of 3 microns (3 x 10m) and the silk can withstand a maximum tension per unit cross section of 1.75 x 10° N/m2. The magnitude of the drag force by the wind on the spider is givne by aD, where v is tc spccd of the wind relative to the spider and D-10-3 Ns/m2 Part a: What is the maximum tension the spider silk can withstand? - max Jo» per area) Carea 2. Part b: Draw a diagram of the spider showing all forces acting on it in thna weight of spider Part c: What is the maximum wind drag on the spider such that the spider silk doesnet break? Spider not moving silk will not brak, Bt T+W20 iTIZ Ter ma Ed IIE/)

Explanation / Answer

First part finds what is the maximum tension that the string can bear.

To find it, we use the formula of stress.

stress = force / area

Using that we get the maximum force, which is the maximum tension.

Now, this tension has to bear both, the weight (vertical) and drag (horizontal).

To combine vertical and horizontal vectors we use pythagoras theorem.

Hence, inveresely, using pythagoras theorem we find the drage force. Taking tension as hypotenuse and weight as vertical side.

Lastly, using the formula of drage force given we find the velocity.

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