Cubic Metal Solid Rock Calculations (1) Physical volume of the rectangular metal

Question

Cubic Metal Solid Rock Calculations (1) Physical volume of the rectangular metallic solid: Vr-LWH (2) Physical volume of the cubic metallic solid from: Vubis um-12 (3) Volume of the rock: Vock Vaupl Wr (4) Calculate the experimental density of the solids from Pese -m/V Error Analysis (1) Instrumental uncertainty in the measurement of the dimensions of the rectangular and cubic metal solids: AL = ½ (smallest scale of measurement)-$(1.00 mm)0.50 mm-+ 0.0050 crn = + 0.00050 m (2) Propagated uncertainty in volume measurement of the rectangular metal solid: -¼ Va , where (3) Propagated uncertainty in volume measurement of the cubic metal solid: AV-(Vmax-Vmin), where Vma (4) Uncertainty in the volume measurement of the rock is given by: dV- with the graduated cylinder)- (smallest scale of measurement (5) Percent difference between the densities you obtained from the experiment and the accepted values: % difference-lempe-pmplpacept)s 1 00- Questions (1) Suppose that when measuring the mass of your rock an error was made and the mass read was smaller than the actual mass. If the volume was correct, would the reported density of the rock be larger or smaller than its actual density? Explain. (2) Suppose that when measuring the volume of your rock an error was made and the volume read was smaller than the actual volume. If the mass was correct, would the reported density of the rock have been larger or smaller than its actual density? Explain. (3) What is your takeaway from this experiment?

Explanation / Answer

(1) desity = mass / volume

So if measured mass is less then actual mass then density is smaller then the actual density

let suppose actual mass = 100 kg and volume = 100 m3

so actual desity = 100 / 100 = 1 kg /m3

now if error is measurement of mass so new mass is 95 kg

so new density = 95 / 100 = 0.95 kg / m3

which is smaller then actual

(2) if measured volume is smaller the density is larger then actual density

so assume previous data of actal mass and volume

new volume = 95 m3

so new density = 100 / 95 = 1.05 kg / m3

which is larger.

(3) I think dont take error is measured data. you miscalulate density of material and you wrongly decide wheather item float on water or not

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