/ ×es2018/FA PHIL-101-4163 x MasteringPhys xyt Topic Logic Practice Secure https

Question

/ ×es2018/FA PHIL-101-4163 x MasteringPhys xyt Topic Logic Practice Secure https://session.masteringphysics.com/myct/itemViev Homework B 118 Problem 2.77 Constants During your summer internship for an aerospace company, you are asked to design a small research rocket. The rocket is to be launched from rest from the eartho's surface and is to reach a maximum height of 960 m above the earth's surface. The rocketa's engines give the rocket an upward acceleration so it moves with acceleration of 160 m/s during the time T that they fire After the engines shut off, the rocket is in free fall. Ignore air resistance Provide

Explanation / Answer

960 m = h + H
where h = height from powered phase
and H = height from unpowered phase

h = ½aT² = ½ * 16m/s² * T² = 8.00m/s² * T²
at which time
v = a*T = 16.0m/s² * T

Unpowered,
H = v² / 2g = (16.0m/s² * T)² / 2*9.8m/s² = 13.1m/s² * T²

Then
960 m = 8.00m/s² * T² + 13.1m/s² * T² = 21.1m/s² * T²
T² = 45.5 s²
T = 6.74 5s

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.