Volume Question: I need help with parts 2 and 3: (part 1) What volume of liquid,

Question

Volume Question: I need help with parts 2 and 3:

(part 1) What volume of liquid, expressed in cm3, would a 16 lb bowling ball displace (diameter=8.5 in).

Use this info and round to proper significant figures: (1 in=2.54 cm; 16oz=1lb; 28.3g=1oz; volume of a sphere (V)=(4/3)r3)

(part 2) What obvious error is in the answer to (part 1)?---explain this one

(part 3) Would a ball equal in volume to the bowling ball described in (part 1), but weighing 1lb, displace the same volume of water as the bowling ball? (consider the relative density of the bowling ball compared to that of water)---explain this one

Explanation / Answer

1. diameter, d = 8.5 in

radius r = 0.10795 m

hence

Volume = V = 4*pi*r^3/3 = 5269.3439715 cm^3

2. density of 16 lb bowling ball = 7.25748/5269.3439715*10^-6 = 1377.28719 kg/m^3 > density of water

so the whole ball will submerge in liquid

and error is the rounding off error ( error in measurement of the diameter of the ball)

3. a ball weighing 1/16 of this ball will have denisty less than density oif wqater and will displace some water and rest of the ball will stay outside water and float

hecne 1 lb ball will displace less water than the 16 lb ball

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