Question1 1 pts In a photoelectric effect experiment, doubling the intensity of

Question

Question1 1 pts In a photoelectric effect experiment, doubling the intensity of the light: Doubles the maximum kinetic energy of emitted electrons Halves the amount of photoelectrons are produced Halves the maximum kinetic energy of emitted electrons Doubles the amount of photoelectrons produced Question2 1 pts The work function represents: The maximum energy of the produced photoelectron The maximum energy of the incident photon required to produce a photoelectron The minimum kinetic energy of the incident photon. The minimum energy of the incident photon required to produce a photoelectron

Explanation / Answer

1.

On doubling the intensity, the number density of photoelectron increased go double

Option (d) is correct  

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2. Work function is considered as minimium energy of photon required to carry out photo electric emission.

Option (d) is correct.

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Comment in case any doubt.. Goodluck

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