Robin would like to shoot an orange in a tree with his bow and arrow. The orange

Question

Robin would like to shoot an orange in a tree with his bow and arrow. The orange is hanging yf=5.00 m above the ground. On his first try, Robin looses the arrow at v0=33.0 m/s at an angle of =30.0° above the horizontal. The arrow has an initial height of y0=1.50 m, and its tip is x=45.0 m away from the target orange.

-Treating the arrow as a point projectile and neglecting air resistance, what is the height of the arrow once it has reached the horizontal position x of the orange?

Use g=9.81 m/s2 for the acceleration due to gravity.

height of the arrow:

-For his second try, Robin decides to change his position but loose the arrow using the same speed and angle as his first try. Assume that the orange remains in the same position.

89.6 m

53.400 m

6.5 m

81.2 m

14.902 m

Explanation / Answer

given
vo = 33.0 m/s

vox = 33.0*cos(30) = 28.6 m/s
voy = 33.0*sin(30) = 16.5 m/s

time taken to reach the x distance, t = x/vox

= 45/28.6

= 1.573 s

height of the the arrow when it travels x distance,

h = yo + voy*t + (1/2)*(-g)*t^2

= 1.5 + 16.5*1.573 + (1/2)*(-9.81)*1.573^2

= 15.3 m <<<<<<<<<-----------------Answer

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