Suppose we throw a light (mass 0.034kg) but moderately hard rubber ball at a wal

Question

Suppose we throw a light (mass 0.034kg) but moderately hard rubber ball at a wall with speed 3.13m/s. For simplicity, assume that the collision is along only the z-axis and that the initial velocity is in the +z-direction.
Part A) If the ball bounces off the wal with the same speed, what is the change in momentum of the ball in kg m/s? (delta)P=<0,0,_> Pz = ______
Part B) In reality, the ball bends (and thus heats up a little) and do it doesn’t bounce off with precisely the initial speed. What if it bounces off with 90.97% of its original speed. What then would be the change in momentum in kg m/s? (delta)P=<0,0,_> Pz = _____
Part C) During the time interval, with which objects did the ball act significantly during the rebounding? [ ] Your Hand [ ] The Earth [ ] The Wall
**Thank you so much for taking the time to answer these parts of my question for it is greatly appreciated! Suppose we throw a light (mass 0.034kg) but moderately hard rubber ball at a wall with speed 3.13m/s. For simplicity, assume that the collision is along only the z-axis and that the initial velocity is in the +z-direction.
Part A) If the ball bounces off the wal with the same speed, what is the change in momentum of the ball in kg m/s? (delta)P=<0,0,_> Pz = ______
Part B) In reality, the ball bends (and thus heats up a little) and do it doesn’t bounce off with precisely the initial speed. What if it bounces off with 90.97% of its original speed. What then would be the change in momentum in kg m/s? (delta)P=<0,0,_> Pz = _____
Part C) During the time interval, with which objects did the ball act significantly during the rebounding? [ ] Your Hand [ ] The Earth [ ] The Wall
**Thank you so much for taking the time to answer these parts of my question for it is greatly appreciated!
Part A) If the ball bounces off the wal with the same speed, what is the change in momentum of the ball in kg m/s? (delta)P=<0,0,_> Pz = ______
Part B) In reality, the ball bends (and thus heats up a little) and do it doesn’t bounce off with precisely the initial speed. What if it bounces off with 90.97% of its original speed. What then would be the change in momentum in kg m/s? (delta)P=<0,0,_> Pz = _____
Part C) During the time interval, with which objects did the ball act significantly during the rebounding? [ ] Your Hand [ ] The Earth [ ] The Wall
**Thank you so much for taking the time to answer these parts of my question for it is greatly appreciated!

Explanation / Answer

Momentum is given by:

P = mass*Velocity = m*V

Change in momentum will be

dP = m*dV = m*(Vf - Vi)

Vf = velocity after bounce

Vi = Velocity before bounce

Part A.

Vi = +3.13 m/sec

Vf = -3.13 m/sec (Since given that speed is same, So only direction will change)

m = mass of ball = 0.034 kg

So,

Pz = m*(Vf - Vi) = 0.034*((-3.13 m/sec) - 3.13 m/sec)

Pz = -0.213 kg-m/sec

Part B.

Vi = +3.13 m/sec

Vf = 90.97% of Vi = 90.97*3.13/100 = -2.85 m/sec (-ve because direction is changed)

So,

Pz = m*(Vf - Vi)

Pz = 0.034*((-2.85) - 3.13)

Pz = -0.203 kg-m/sec

Part C.

during the rebounding ball was in contact with wall, So it acted with the wall significantly.

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