The graph below shows three plots of velocity (Vb) versus substrate concentratio

Question

The graph below shows three plots of velocity (Vb) versus substrate concentration ((S]) Determine which curve represents an enzyme's reaction velocity without any inhibitor present, which curve represents the velocity's in the presence of a mixed inhibitor, and which curve represents the velocity in the presence of a competitive inhibitor. Use data from the plots ol versus (S) without an inhibitor and in the presence of a competitive inhibitor to calculate K when 7.0 mu M of the inhibitor is present.

Explanation / Answer

Ki = [I] / (alpha-1)

= [7] / [(5/2)-1] = 4.66

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