i want the solution for the following problem:- Q1. A man is stationary and he o
ID: 1893495 • Letter: I
Question
i want the solution for the following problem:-Q1. A man is stationary and he observes that the rain is striking him at 60? from the horizantal. When he starts moving with a velocity of 25 m/s, then he observes that the rain strikes him at an angle of 30? from the horizantal. Calculate actual velocity of rain.
Q2.Rain appear to be falling vertically to an observer who is moving on the road with 6kmph.When he double his speed rain appear to be falling at an angle 30? with vertical . find the velocity of the rain.(Plz If possible solve this without using Calculas or maxima & minima.As i have not yet studied these concept.)
Please solve these question as soon as possible.PLz solve this question with diagram so that i will understand these question more easily .
Thanks in advance
Explanation / Answer
Q1.. Let the velocity of the rain be v. When the man was standing the rain was at angle 60 deg the horizontal. Now the horizontal component of velocity=vcos 60 Vertical component=v sin 60 Now, when he moves with 25 m/s. The horizontal velocity of rain wrt man =25+v cos 60 The vertical component remains v sin 60 The man feels rain striking him at 30 deg from horizontal So, (Vertical vel. of rain wrt man)/(Horizontal velocity wrt man)=tan 30 i.e. (v sin 60)/(25+v cos60)=tan 30 Solve to get v=25 m/s Q2... When he is moving with 6 kmph rain appears to be falling vertically.Hence the horizontal component of the velocity of rain is equal to velocity of man = 6 kmph Now, when the speed is doubled horizontal velocity of rain wrt man = 6 kmph vertical component of velocity of rain =6 tan 30 horizontal component=6 kmph(already calculated) Hence we get v(rain)=6sqrt(3) m/s at 30 deg from horizontal
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