please explain the correct options: a beam of pions(+) is incident on a proton t

Question

please explain the correct options:
a beam of pions(+) is incident on a proton target, giving rise to process
+p n ++++
(A) assuming that the decacy proceeds through strong interactions, the total isospin I and its third component I3 for the decay products,are
1. I=3/2 , I3=3/2
2. I=5/2 , I3=5/2
3. I=5/2 , I3=3/2
4. I=1/2 , I3=-1/2
(B) using isospin symmetry,the cross-section for the above process can be related to that of the process
1. - n p--

2.-(p) (n) --

3. +n p+-

4. +(p) n+-

where (p)=p bar(antiproton) and (n)=n bar (anti neutron)

Explanation / Answer

3. I=5/2 , I3=3/2 3. p+n ? pp+p-

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