A 0.368 m long metal bar is pulled to the left by an applied force F . The bar r

Question

A 0.368 m long metal bar is pulled to the left by an applied force F . The bar rides on parallel metal rails connected through a 43.1 ohms resistor, as shown in the following figure , so the apparatus makes a complete circuit. You can ignore the resistance of the bar and rails. The circuit is in a uniform 0.623 T magnetic field that is directed out of the plane of the figure. http://session.masteringphysics.com/problemAsset/1331235/8/2929.jpg

Part B: At the instant when the bar is moving to the left at 5.90 m/s, what is the rate at which the applied force is doing work on the bar?

Explanation / Answer

emf induced = l.(v*b)

use right hand thumb rule to get (v*b)

Part A: At the instant when the bar is moving to the left at 5.90, is the induced current in the circuit is counterclockwise.

Part B: At the instant when the bar is moving to the left at 5.90 m/s, what is the rate at which the applied force is doing work on the bar = v2/r = (vblsin)2 /r = 0.042 J/s

=

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