Given two particles with Q = 1.70-C charges as shown in the figure below and a p

Question

Given two particles with Q = 1.70-C charges as shown in the figure below and a particle with charge q = 1.23 X 10^-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = infinity .) (a) What is the net force exerted by the two 1.70-C charges on the test charge q? N (b) What is the electric field at the origin due to the two 1.70-C particles? N/C (c) What is the electrical potential at the origin due to the two 1.70-C particles? What is the contribution to the potential due to one of the 1.70-C charges? How do you then account for both charges? kV

Explanation / Answer

all the answers given are correct (a)force is equal and in opposite direction so F=0 (b)eletric field is same in magnitude and opposite direction so E=0 (c)potential is sum of the two potentials=3.82e4=2*k*1.7e-6*1/(0.8) here k is columbs constant

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