A) Two 10 Ohms resistors are connected to a 5 V battery. Under which conditions

Question

A) Two 10 Ohms resistors are connected to a 5 V battery. Under which conditions (parallel or series) will the battery supply the most power and how much power will the battery supply? B) Three 15 ? resistors are connected in parallel. What battery potential is required such that each resistor carries a current of 0.5 A? C) A resistor of resistance R is connected to a battery that supplies potential V. This circuit dissipates a power P. If the resistance is doubled and the potential stays constant, what is the new power in terms of P? A) 4P B) P C) P/2 D) P/4 E) 2P

Explanation / Answer

A) in series

R = 20

i = 5/20 = 0.25

P = i2R = 1.25 W

in parallel

R = 5

i = 1A

P = 0.52 x 10 x 2

P = 5 J

hence power is more in parallel connection

B) R = 5

hence,

total current i = 3 x 0.5 = 1.5

V = iR = 1.5 x 5 = 7.5 V

C) P = V2/R

now if R is doubled

P' = P/2

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