A light ray goes through two thick rectangular slabs of glass, each of the same

Question

A light ray goes through two thick rectangular slabs of glass, each of the same uniform thickness. The first slab has index of refraction n1 and the second n2. If n1 < n2, how does the original angle of incidence (theta i) into the first slab compare to the final angle of refraction (theta f) where the ray leaves the second slab going back into the air?

A Angle of incidence > angle of refraction
B Angle of incidence < angle of refraction
C Angle of incidence = angle of refraction
D Angle of incidence = (n1/n2) angle of refraction
E More information needed


Any help and explanation with this problem would be very much appreciated!!!

Explanation / Answer

sin1/sini = 1/n1, sin2/sin1 = n1/n2, sinf/sin2 = n2/1

=>sinf/sini = sin1/sini * sin2/sin1 * sinf/sin2 = (1/n1)*(n1/n2)*(n2/1) = 1

=>sinf = sini

=>f = i

=>Angle of incidence = Angle of refraction..........Option C

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