A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as

Question

A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as functions of time are given by x = 18.1t and y = 3.60t ? 4.57t2, where x and y are in meters and t is in seconds. (a) Write a vector expression for the ball's position as a function of time, using the unit vectors and . (Give the answer in terms of t.) r = By taking derivatives, do the following. (Give the answers in terms of t.) (b) obtain the expression for the velocity vector as a function of time v= (c) obtain the expression for the acceleration vector as a function of time a = (d) Next use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the golf ball at t = 2.94 s. r____ = m v ____ = m/s a______ = m/s2

Explanation / Answer

The horizontal motion of the ball is at cosntant speed using equation of x = Vx*t Given x = 18*t We conclude that Vx = 18 m/s Comparing the given y(t) equation of y(t) = 4.5* - 4.9*t^2 with the equation of free fall of h(t) = h0 + Vy*t + (1/2)*g*t^2 We see that h0=0 Vy=4.5 m/s (Vy>0) a=-4.9 (a

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