The helicopter view in the figure shows two people pulling on a stubborn mule. T

Question

The helicopter view in the figure shows two people pulling on a stubborn mule. The person on the right pulls with a force 1 of magnitude 114 N and direction of ?1 = 55.0. The person on the left pulls with a force 2 of magnitude 102.6 N and direction of ?2 = 65.0. (a) Find the single force that is equivalent to the two forces shown. The forces are measured in units of newtons (symbolized N). N + N (b) Find the force that a third person would have to exert on the mule to make the resultant force equal to zero. N + N

Explanation / Answer

If this is wrong please re-post this info So using components F1x = F18cos(60) = 125N*cos(60) = 62.5N F1y = f1*sin(60) = 125N*sin(60) = 108.3 For F2 we have F2x = 85*cos(-75) = 22.0N and F2Y = 85N*sin(-75) = -82.1 So Fx = F1x + F2x = 62.5 + 22 = 84.5N and Fy = 108.3 - 82.1 = 26.2N So F = sqrt(84.5^2 + 26.2^2) = 88.5N and ? = arctan(Fy/Fx) = arctan(26.2/84.5) = 17.2o b) To make the net force zero a third person would pull with a force = 88.5N and at an angle od 17.2+180 = 197.2o

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