A 10 kg block descends on a plane inclined at 30 degree as shown. Its attitude,

Question

A 10 kg block descends on a plane inclined at 30 degree as shown. Its attitude, where it starts from rest, is 20 meters higher then when it reaches the bottom. What is its acceleration along the plane if Mk = 0 ? Starting from rest, how long does it take to get to the bottom? What is its speed at the bottom? Compare its kinetic energy ½ Mv2 with its change in potential energy: -Mg (20m). If Mk = 0.3, what is the frictional force? What is its speed u at the bottom if Mk = 0.3 Compare the work done by friction and the change in potential energy with the final kinetic energy.

Explanation / Answer

a. acceleration=9.8sin30=4.9m/s^2 b. time=sqrt(10*cot30*2/9.8)=1.88secs c. velocity=sqrt(2*9.8*10)=14m/s d. ke=pe e. 0.3*10*9.8*cos30=25.46N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.