A load of bricks with mass m1 = 15.8 hangs from one end of a rope that passes ov

Question

A load of bricks with mass m1 = 15.8 hangs from one end of a rope that passes over a small, frictionless pulley. A counterweight of mass m2= 27.0 is suspended from the other end of the rope, as shown in the figure. (Figure 1) The system is released from rest. Use g= 9.80 for the magnitude of the acceleration due to gravity.

(Figure 1) http://session.masteringphysics.com/problemAsset/1260016/3/YF-05-51_new.jpg


A
What is the magnitude of the upward acceleration of the load of bricks? (expressed in m/s^2)

B
What is the tension in the rope while the load is moving? (Expressed in Newtons)

Explanation / Answer

here is right solution with correct values not copy past
bricks
15.8*a=T-15.8*9.8

counterweight
27*a=27*9.8-T
solve for T first
T/15.8-9.8=a
9.8-T/27=a
T/15.8-9.8=9.8-T/27
T(1/15.8+1/27)=2*9.8
T=195.35 N
a=2.56 m/s^2

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