The figure below shows four circular Amperian loops (a, b, c, d) and, in cross s

Question

The figure below shows four circular Amperian loops (a, b, c, d) and, in cross section, four long circular conductors (the shaded regions), all of which are concentric. Three of the conductors are hollow cylinders; the central conductor is a solid cylinder. The currents in the conductors are, from smallest radius to largest radius, 4 A out of the page, 9 A into the page, 5 A out of the page, and 3 A into the page. Rank the Amperian loops according to the magnitude of B

Explanation / Answer

Hey, the answer is b>a>d>c The way I got this is by adding the currents of the conductors on the inside of the Amperian loops. Current going in opposite directions cancels each other out. So, the greater the magnitude of the current inside the loop, the greater the magnetic field will be by the equation B = [(_0)*i]/(2?r)

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