A man of mass m m = 95 kg decides to paint his house. To do this, he builds a pl
ID: 1904841 • Letter: A
Question
A man of massmm= 95 kgdecides to paint his house. To do this, he builds a platform using a uniform beam with a mass ofmb= 100 kgand a length ofL = 7 meters. The beam is supported by two sawhorses, as shown in the diagram above.
F =
How far from the end of the beam (the end closest to supportA) does the person have to stand to unbalance the beam?
x =
Later that day, after thinking about how cool rotational dynamics really is, the man decides to conduct an experiment. He removes one of the supports and places the other as shown in the diagram. Standing at the end of the board, he has his daughter place paint cans, each of massmc= 2.9375 kg, on the opposite end. How many cans will the girl have to place on the board to provide the best balance? (You may neglect the actual length of the board that both the man and the cans occupy. Assume both are points at the ends of the board.) Also, take the axis of rotation about the sawhorse.
Number of cans =
A man of massmm= 95 kgdecides to paint his house. To do this, he builds a platform using a uniform beam with a mass ofmb= 100 kgand a length ofL = 7 meters. The beam is supported by two sawhorses, as shown in the diagram above. 1) If the man stands over the support at pointB, calculate the force exerted by the beam on the support atA. F = N 2)image showing a beam supported by two supports with a person near the right end of the beam How far from the end of the beam (the end closest to supportA) does the person have to stand to unbalance the beam? x = m 3)image showing a beam supported by one support with a person at the left end and a paint can at the right end Later that day, after thinking about how cool rotational dynamics really is, the man decides to conduct an experiment. He removes one of the supports and places the other as shown in the diagram. Standing at the end of the board, he has his daughter place paint cans, each of massmc= 2.9375 kg, on the opposite end. How many cans will the girl have to place on the board to provide the best balance? (You may neglect the actual length of the board that both the man and the cans occupy. Assume both are points at the ends of the board.) Also, take the axis of rotation about the sawhorse. Number of cans =Explanation / Answer
a) -3N + 1.5 * 100*9.81 = 0 N=490.5 b) A + B -9.81*100 - 9.81*95 = 0 and 2A + 5B - 3.5*100*9.81 - x*95*9.81=0 if A = 0 B=1913 then 5*1913 - 3.5*100*9.81 - x*95*9.81=0 x= 6.58 m if B = 0 A = 1913 2*1913 - 3.5*100*9.81 - x*95*9.81=0 x = 0.42 m c)95*3 - N*4*2.9375 - 100*.5 = 0 N=20
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