A wheel of radius 0.360 m starts from rest and accelerates uniformly to an angul

Question

A wheel of radius 0.360 m starts from rest and accelerates uniformly to an angular speed of 18.0 rad/s in 6.00 s. 1) Calculate the final linear speed of a point on the rim of the wheel. In other words, relate the velocity v to the angular velocity ? 2)Calculate the angular acceleration of the wheel. 3)Calculate the linear (tangential) acceleration of a point on the rim of the wheel. In other words, relate the acceleration a to the angular acceleration ? 4)Calculate the angular displacement of the wheel. NOTE: The angular displacement is ?? in radians. You must specify "rad" as the unit.

Explanation / Answer

1)

v = R = 0.360 * 18 = 6.48 m/s

2)

= /t = 18/6 = 3 rad/s2

3)

a = R = R (/t) = 0.360 * 18/6 = 1.08 m/s2

4)

= (^2)/2 = 18*18/2/1.08 = 150 rad

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