A 1.7 kg mass is held at rest on top of a frictionless and horizontal table. A l
ID: 1905669 • Letter: A
Question
A 1.7 kg mass is held at rest on top of a frictionless and horizontal table. A light string loops over a pulley which is in the shape of a 10 cm radius solid disk which has a mass of 1.7 kg. The light string then supports a mass of 1.7 kg which is hanging in air a)The mass on the table is released and the suspended mass falls. What is the acceleration of the falling mass b)What is the tension in the string which is attached to the sliding mass on the table? c)What is the tension of the string which supports the hanging mass?Explanation / Answer
mass of all objects are same say m.
(a)
hanging one
mg-T1 = ma
pulley
T1-T2=I/r
on table one
T2 = ma
and = a/r
adding all equations
mg = 2ma + I/r
=> mg = 5ma/2 (I = mr^2/2)
=> a = 2g/5 = 3.92 m/s^2.
(b)
T2 = ma = 6.644 N
(c)
T1 = mg - ma = 10.016 N
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