hello can you please show the steps and the answers of each step so i can figure

Question

hello can you please show the steps and the answers of each step so i can figure out where the numbers come from/ thank you. A mass m1 = 5.7 kg rests on a frictionless table and connected by a massless string to another mass m2 = 3.9 kg. A force of magnitude F = 37.0 N pulls m1 to the left a distance d = 0.77 m. The work done by the force F on the two block system is 28.49J and the work done by the normal force on m1 and m2 is 0 J . What is the final speed of the two blocks in m/s and how much work is done by the tension (in-between the blocks) on block m2?

Explanation / Answer

By KE equation:

0.5*m*V^2 = 28.49

0.5*(5.7+3.9)*V^2 =28.49

V = 2.436 m/s

Speed of both block is 2.436 m/s

Work done by tension = 0.5*3.9*2.436^2 = 11.574 J

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.