The combination of an applied force and a friction force produces a constant tot

Question

The combination of an applied force and a friction force produces a constant total torque of 36.5 N middot m on a wheel rotating about a fixed axis. The applied force acts for 6.20 s. During this time, the angular speed of the wheel increases from 0 to 9.9 rad/s. The applied force is then removed, and the wheel comes to rest in 60.3 s. Find the moment of inertia of the wheel, kg middot m2 Find the magnitude of the torque due to friction. N middot m Find the total number of revolutions of the wheel during the entire interval of 66.5 s. revolutions

Explanation / Answer

a)
Angular acceleration = (2- 1)/t

I is known. Calculate I
===========================
b)
The wheel comes to rest only due to the frictional torque (friction)

(friction) = I '
' is known
(friction) = I * '
==============================
c)
in time 6.20s
= 0.5 t^2

Or from average angular velocity *time we know its value

In time 66.5 s
Find radians

Total angle traversed
Add both angles=Sum
Sum/ (2) revolutions Gives us revolutions.
========================

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.