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When you arrive at Duke\'s Dude Ranch, you are greeted by the large wooden sign

ID: 1906801 • Letter: W

Question

When you arrive at Duke's Dude Ranch, you are greeted by the large wooden sign shown in the figure(Figure 1) . The left end of the sign is held in place by a bolt, the right end is tied to a rope that makes an angle of 20.0 degrees with the horizontal. The sign is uniform, 3.20 m long, and has a mass of 15.0 kg .




Q: What are the Fhorizontal and the Fvertical values in N?

When you arrive at Duke's Dude Ranch, you are greeted by the large wooden sign shown in the figure(Figure 1) . The left end of the sign is held in place by a bolt, the right end is tied to a rope that makes an angle of 20.0 degrees with the horizontal. The sign is uniform, 3.20 m long, and has a mass of 15.0 kg . Q: What are the Fhorizontal and the Fvertical values in N?

Explanation / Answer

from equilibrium, the F acting on the sign by the bolt is the same as the force acting on the sign by the rope. summation of forces in the x direction= Fcos(theta)-Tcos(20)=0 therefore Fcos(theta)=Tcos(20). you assume at theta=20, therefore F=T. So the summation of forces in the y direction=Fsin(20)+Tsin(20)-mg=2Tsin(20)-mg=0. since m=15kg, and g=9.81 m/s^2 then T=215.12N. the horizontal F = Tcos(20)=202.15N and the vertical is Tsin(20)=73.58N. double check me on the math but the equations are correct.

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